Byte.parseByte throws NumberFormatException for value "95", radix: 16

I have question about parsing hex string. Java 6u25 When I call Byte.parseByte("95", 16) I get. java.lang.NumberFormatException: Value out of range. Value:"95" Radix:16 at java.lang.Byte.parseByte(Byte.java:153) 95 hex is 149 dec, Integer value '149' can be cast to valid byte value -107 Is the exception correct? Thank you very much for answer Martin JANDA jandam@crcdata.cz Code from Byte.java public static byte parseByte(String s, int radix) throws NumberFormatException { int i = Integer.parseInt(s, radix); if (i < MIN_VALUE || i > MAX_VALUE) throw new NumberFormatException( "Value out of range. Value:\"" + s + "\" Radix:" + radix); return (byte)i; }