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<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt"><o:p> </o:p></span></p>
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<p class="MsoNormal" style="margin-bottom:12.0pt"><b><span style="color:black">From:
</span></b><span style="color:black">Maurizio Cimadamore <maurizio.cimadamore@oracle.com><br>
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<p>> What I don't get is why block 27 gets to be reused. In fact, if we end up in block 27, there's no exit - and we go straight to block 1, which will enter again. Is this correct?</p>
<p><span style="font-size:11.0pt">Yes, it is a the while(true) loop, where you re-enter the region, but the branch instruction is outside the try block.<o:p></o:p></span></p>
<p>> If we wanted to exit the region from block 27, then we'd also need to split, as we might need to exit either %1 or %5 from there, no?</p>
<p><span style="font-size:11.0pt">block 27 is the exception handler of the </span>
outer try region(s), so no need to exit it (them)<span style="font-size:11.0pt"><o:p></o:p></span></p>
<p><o:p> </o:p></p>
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