why unrestricted closures are always void?

[Neal Gafter]

Unrestricted closures are not so constrained: they can have any return type.

On Fri, Nov 14, 2008 at 6:25 PM, Vladimir Kirichenko <
vladimir.kirichenko at gmail.com> wrote:

> This makes impossible to implement functional-style control abstractions
> like generators:
>
> Iterable<Integer> squares = yield(int i : someIterable()) { i * i }
>
> int[] sqa =  for collect(int i : array) { i * i }
>
> It looks very inconsistent to be able to use control abstraction with
> "void" code and to be unable to use it with "code with result".  It places
> major limitation to usage of control abstractions. Is this really necessary?
>
> --
> Best Regards,
> Vladimir Kirichenko
>
>
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