Huston, we have a problem !

[Neal Gafter]

On Fri, Feb 18, 2011 at 9:10 AM, Florian Weimer <fweimer at bfk.de> wrote:

> Clearly, those a different at compile time.  What I'm looking for is a
> case where both Foo and Foo<> result in legal expressions at compile
> time and produce different byte code.
>

*public class X<T> {
    public X(T t) {}
    public T get() { return null; }
    public static int f(String s) { return 1; }
    public static int f(Object o) { return 2; }
    public static void main(String[] args)
    {
        System.out.println(f(new X<>("").get()));
        System.out.println(f(new X("").get()));
    }
}*