how to tell 2 methods are override-equivalent

Jonathan Gibbons jonathan.gibbons at
Tue Mar 21 21:28:09 UTC 2017


Use Element.asType() to move from the Element world to the TypeMirror world.

Use Types.asElement(TypeMirror) to go in the reverse direction, from a 
TypeMirror to an Element.
but note the reverse direction is lossy and may throw exceptions:
     e.g. for type "int", there is no direct element equivalent;  for 
type List<String>, the element will be the declaration List<T>

-- Jon

On 3/16/17 8:15 PM, Hamlin Li wrote:
> Hi,
> ( I'm not sure if this is the right alias to ask the question, please 
> help forward if necessary. )
> I have a question about telling whether one method is subsignature of 
> another one. My situation is,
> 1. there is a TypeElement *t1 *which represents, and a 
> ExecutableElement *m1* which represents 
> getContent(java.lang.Class*<?>*[]),
> 2. there is a String *t2* which is "", and another String 
> *m2 *which is "getContent(java.lang.Class[])".
> The difference between m1 and m2 is that, m1 is an instance of 
> ExecutableElement, m2 is an instance of String; there is a wildcard 
> type argument in m1.
> Is there a way to tell whether m1 and m2 are override-equivalent, m2 
> is subsignature of m1?
> I suppose I should use 
> javax.lang.model.util.Types.isSubsignature(ExecutableType m1, 
> ExecutableType m2), but I don't know how can I convert 
> ExecutableElement *m1* and String *m2* to**ExecutableType.
> Or I'm in wrong direction?
> Thank you
> -Hamlin

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