how to tell 2 methods are override-equivalent

[Jonathan Gibbons]

Hamlin,

Use Element.asType() to move from the Element world to the TypeMirror world.
http://download.java.net/java/jdk9/docs/api/javax/lang/model/element/Element.html#asType--

Use Types.asElement(TypeMirror) to go in the reverse direction, from a 
TypeMirror to an Element.
http://download.java.net/java/jdk9/docs/api/javax/lang/model/util/Types.html#asElement-javax.lang.model.type.TypeMirror-
but note the reverse direction is lossy and may throw exceptions:
     e.g. for type "int", there is no direct element equivalent;  for 
type List<String>, the element will be the declaration List<T>

-- Jon

On 3/16/17 8:15 PM, Hamlin Li wrote:
>
> Hi,
>
> ( I'm not sure if this is the right alias to ask the question, please 
> help forward if necessary. )
>
> I have a question about telling whether one method is subsignature of 
> another one. My situation is,
>
> 1. there is a TypeElement *t1 *which represents java.net.URL, and a 
> ExecutableElement *m1* which represents 
> getContent(java.lang.Class*<?>*[]),
>
> 2. there is a String *t2* which is "java.net.URL", and another String 
> *m2 *which is "getContent(java.lang.Class[])".
>
> The difference between m1 and m2 is that, m1 is an instance of 
> ExecutableElement, m2 is an instance of String; there is a wildcard 
> type argument in m1.
>
>
> Is there a way to tell whether m1 and m2 are override-equivalent, m2 
> is subsignature of m1?
>
> I suppose I should use 
> javax.lang.model.util.Types.isSubsignature(ExecutableType m1, 
> ExecutableType m2), but I don't know how can I convert 
> ExecutableElement *m1* and String *m2* to**ExecutableType.
>
> Or I'm in wrong direction?
>
>
> Thank you
>
> -Hamlin
>

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