Raw strings starting/ending with backtick

[Weijun Wang]

> On Nov 24, 2018, at 9:11 PM, Jim Laskey <james.laskey at oracle.com> wrote:
> 
> There are several  approaches but the simplest is using strip().  Example,
> 
>    `` `abc` ``.strip()
> 
> Concat is another approach,
> 
>    “`” + `abc` + “`”

But this means the literal inside the constant pool of the class will be "`abc` ", right? This is a little uncomfortable to me.

> 
> Not perfect but other delimiter choices also have these edge cases.  

How about the Rust r###"..."### style?

Thanks
Max

> 
> Cheers,
> 
> — Jim
> 
> 
> Sent from my iPad
> 
>> On Nov 24, 2018, at 8:55 AM, Attila Kelemen <attila.kelemen85 at gmail.com> wrote:
>> 
>> Hi,
>> 
>> Reading the JEP on raw string literals, I saw no mentions of the case when a string starts (or ends) with backtick. I guessed, that maybe the compiler will close the literal when it finds more than half the number of backticks than the beginning (nothing implied this behaviour just tried it and I know that it might be very suprising in other cases). I have tried with the latest early access compiler and (not too suprisingly) it didn't behave this way and simply failed when starting the literal with a backtick.
>> 
>> My question is, of course: What is the strategy for this case? Or is it explicitly ignored as too much of an edge case (and left to the developer to deal with)?
>> 
>> Thanks,
>> Attila Kelemen
>