Need reviewer: JDK 8 CR for Support Integer overflow

[Roger Riggs]

The boolean expression can be refactored. (Only bit-31 is significant).
But it becomes pretty inscrutable.

(x ^ r)<  0&&  (x ^ y)>= 0  becomes

(x ^ r)<  0&&  (~(x ^ y))<  0  becomes

((x ^ r)&  ~(x ^ y))<  0

Roger



On 02/03/2012 07:12 AM, Florian Weimer wrote:
> * Eamonn McManus:
>
>> On 3 February 2012 00:11, Florian Weimer<fweimer at bfk.de>  wrote:
>>> Would it make sense to replace (x ^ r)<  0&&  (x ^ y)>= 0
>>> with (x ^ y ^ r)<  0?
>> That would not be correct. For example, it would signal overflow for -1 + 1.
> Oops.  But there has to be a way to implement this using just one
> comparison.
>