How to extract matches from (\d+[hms])+ ?

[Wang Weijun]

On Sep 25, 2014, at 13:06, Guy Steele <guy.steele at oracle.com> wrote:

> (A lurker sticking his nose in here! :-)  Is it your intent also to match "30s1h" or "20m30m" as a time duration?
> 
> If not, you might be better off with a pattern such as "((\\d+)h)?((\\d+)m)?((\\d+)s)?" and then the whole problem caused by the outer "+" iteration disappear (but you may need to check whether the original string was empty).

Yes, this is much better.

> 
> But maybe that takes all the fun out of it.

Let someone else enjoy it then. :-)

Thanks
Max

> 
> --Guy Steele
> 
> On Sep 25, 2014, at 12:51 AM, Wang Weijun <weijun.wang at oracle.com> wrote:
> 
>> Hi Sherman
>> 
>> I want to match a time duration like "1h20m30s" and "2h". It looks like if I directly use the pattern "((\\d+)([hms]))+", group(2) and group (3) only return the last match (i.e. 30 and s for 1h20m30s). So I tried multiple matching with "(\\d)([hms])" only, but find() does not always match from the beginning, and lookingAt() does not advance after one call.
>> 
>> This is my code now;
>> 
>> int start = 0;
>> while (true) {
>> if (!m.find() || m.start() != start) {
>>   throw new Exception();
>> }
>> start = m.end();
>> print(m.group(1), m.group(2));
>> if (m.hitEnd()) break;
>> }
>> print("Done");
>> 
>> Is this the correct way?
>> 
>> Thanks
>> Max
>> 
>