RFR 8193832: Performance of InputStream.readAllBytes() could be improved
Peter Levart
peter.levart at gmail.com
Wed Dec 20 11:45:03 UTC 2017
Hi Brian,
On 12/20/2017 12:22 AM, Brian Burkhalter wrote:
> On Dec 19, 2017, at 2:36 PM, Brian Burkhalter <brian.burkhalter at oracle.com> wrote:
>
>>> You can also simplify the “for(;;) + break" into a do while loop:
>>>
>>> do {
>>> int nread = 0;
>>> ...
>>> } while (n > 0);
>> Good suggestion but I think that this needs to be "while (n >= 0)."
> Updated version here:
>
> http://cr.openjdk.java.net/~bpb/8193832/webrev.02/
>
> Thanks,
>
> Brian
Looks good. There is one case that could be further optimized. When
result.length <= DEFAULT_BUFFER_SIZE, the allocation of ArrayList could
be avoided. Imagine a use case where lots of small files are read into
byte[] arrays. For exmaple:
public byte[] readAllBytes() throws IOException {
List<byte[]> bufs = null;
byte[] result = null;
byte[] buf = new byte[DEFAULT_BUFFER_SIZE];
int total = 0;
int n;
do {
int nread = 0;
// read to EOF which may read more or less than buffer size
while ((n = read(buf, nread, buf.length - nread)) > 0) {
nread += n;
}
if (nread > 0) {
if (MAX_BUFFER_SIZE - total < nread) {
throw new OutOfMemoryError("Required array size too
large");
}
total += nread;
byte[] copy = (n < 0 && nread == DEFAULT_BUFFER_SIZE) ?
buf : Arrays.copyOf(buf, nread);
if (result == null) {
result = copy;
} else {
bufs = new ArrayList<>(8);
bufs.add(result);
bufs.add(copy);
}
}
} while (n >= 0); // if the last call to read returned -1, then
break
if (bufs == null) {
return result == null ? new byte[0] : result;
}
result = new byte[total];
int offset = 0;
for (byte[] b : bufs) {
System.arraycopy(b, 0, result, offset, b.length);
offset += b.length;
}
return result;
}
There is a possibility that JIT already avoids allocating ArrayList
utilizing EA if all involved ArrayList methods inline, so this potential
optimization should be tested 1st to see if it actually helps improve
the "small file" case.
Regards, Peter
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