Bug in parallel sorting of float / double
David Holmes
david.holmes at oracle.com
Wed Jul 24 12:39:05 UTC 2019
Hi Vladimir,
On 24/07/2019 8:53 pm, Vladimir Yaroslavskiy wrote:
> Hi all,
>
> I've found bug in parallel sorting of float / double arrays in the latest JDK.
>
> When float / double values are sorted, additional actions are
> required: NaNs must be moved to the end and negative zeros
> must be placed before positive zeros.
>
> Current implementation of Arrays.parallelSort(float[] / double [])
> invokes parallel merge sort from ArraysParallelSortHelpers class,
> but it doesn't arrange NaNs and -0.0.
It ultimately uses DualPivotQuicksort which AFAICS does have code to
arrange NaNS:
static void sort(float[] a, int left, int right,
float[] work, int workBase, int workLen) {
/*
* Phase 1: Move NaNs to the end of the array.
*/
while (left <= right && Float.isNaN(a[right])) {
--right;
}
and also order +/-0
/*
* Phase 3: Place negative zeros before positive zeros.
*/
where does the bug arise?
Thanks,
David
-----
> @Alan, Brent, Laurent
> Could you please file a bug?
>
> New optimized version of DualPivotQuicksort (which is under review) works fine and
> doesn't contain this bug. Please, look at my test case to reproduce it.
>
> ----------------------------------------------------------------------------------------------------------------------
> import java.util.Random;
>
> public class FailedFloat {
>
> private static final int MAX_N = (1 << 13) /* Arrays.MIN_ARRAY_SORT_GRAN */ + 10;
>
> public static void main(String[] args) {
> float[] a = new float[MAX_N];
> random(a);
> java.util.Arrays.parallelSort(a);
> check(a);
> System.out.println("PASSED");
> }
>
> private static void random(float[] a) {
> Random random = new Random(777);
> for (int i = 0; i < MAX_N; i++) {
> a[i] = random.nextBoolean() ? -0.0f : 0.0f;
> }
> }
>
> private static void check(float[] a) {
> for (int i = 0; i < a.length - 1; ++i) {
> if (Float.floatToRawIntBits(a[i]) == 0 && Float.floatToRawIntBits(a[i + 1]) < 0) {
> throw new RuntimeException(a[i] + " goes before "+ a[i + 1] + " at position " + i);
> }
> }
> }
> }
> ------------------------------------------------------------------------------------------------------------------------
> Thank you,
> Vladimir
>
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