RFR: 8334755: Asymptotically faster implementation of square root algorithm [v30]

[fabioromano1]

On Thu, 18 Jul 2024 15:01:22 GMT, fabioromano1 <duke at openjdk.org> wrote:

>> It takes about 5 s on my laptop.
>
>> I mean only restricted to unsigned `long` perfect squares, something like the following, but written as a proper test
>> 
>> ```
>>         long i = 0;
>>         for (; i < 1L << 32; ++i) {
>>             long x = i * i;
>>             long s = (long) Math.sqrt(x >= 0 ? x : x + 0x1p64);
>>             if (!(s + 1 == i || s == i)) {
>>                 System.out.format("oops... i=%d, but s=%d%n", i, s);
>>                 System.exit(1);
>>             }
>>         }
>> ```
> 
> So, it is okay although the code does not test directly BigInteger.sqrt()?

I found the way: I can test directly the code through `java.math.Accessor.java`

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PR Review Comment: https://git.openjdk.org/jdk/pull/19710#discussion_r1683022159