RFR: 8077587: BigInteger Roots [v52]

Raffaello Giulietti rgiulietti at openjdk.org
Tue Jul 29 11:09:00 UTC 2025


On Mon, 28 Jul 2025 14:03:16 GMT, fabioromano1 <duke at openjdk.org> wrote:

>> This PR implements nth root computation for BigIntegers using Newton method.
>
> fabioromano1 has updated the pull request incrementally with one additional commit since the last revision:
> 
>   Zimmermann suggestion

src/java.base/share/classes/java/math/MutableBigInteger.java line 2002:

> 2000:             // Try to shift as many bits as possible
> 2001:             // without losing precision in double's representation.
> 2002:             if (bitLength - (sh - shExcess) <= Double.MAX_EXPONENT) {

Here's an example of what I mean by "documenting the details"
Suggestion:

            if (bitLength - (sh - shExcess) <= Double.MAX_EXPONENT) {
                /*
                 * Let x = this, P = Double.PRECISION, ME = Double.MAX_EXPONENT,
                 * bl = bitLength, ex = shExcess, sh' = sh - ex
                 *
                 * We have
                 *      bl - (sh - ex) ≤ ME  ⇔  bl - (bl - P - ex) ≤ ME  ⇔  ex ≤ ME - P
                 * hence, recalling x < 2^bl
                 *      x 2^(-sh') = x 2^(ex-sh) = x 2^(-bl+ex+P) = x 2^(-bl) 2^(ex+P)
                 *          < 2^(ex+P) ≤ 2^ME < Double.MAX_VALUE
                 * Thus, x 2^(-sh') is in the range of finite doubles.
                 * All the more so, this holds for ⌊x / 2^sh'⌋ ≤ x 2^(-sh'),
                 * which is what is computed below.
                 */

Without this, the reader has to reconstruct this "proof", which is arguably harder than just verifying its correctness.

OTOH, the statement "Adjust shift to a multiple of n" in the comment below is rather evident, and IMO does not need further explanations (but "mileage may vary" depending on the reader).

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PR Review Comment: https://git.openjdk.org/jdk/pull/24898#discussion_r2239411008


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