narrow_klass_shift is nonzero on jdk9...

Coleen Phillimore coleen.phillimore at oracle.com
Fri Jan 23 17:08:05 UTC 2015


Hi Andrew,

Allocating this compressed class space is unfortunately complicated.  I 
think you're looking at an old version of the code though, Goetz has 
changed this and moved it to virtualspace.cpp.

The compressed class space is allocated above the heap because we want 
the java heap to have the most favorable compression algorithm.

The code also has a special case so that for zero-based compressed oops; 
it saves space for the compressed class space to also get zero-based 
compressed class pointers.  Decoding klasses without a base is better 
than decoding without a shift.   The code doesn't try to fit both 
compressed oops and compressed class pointers in the lower 4G.  It's 
generally improbable since the compressed class space is 1G size 
(because growing it is not supported atm)  and doing so generally pushes 
the java heap over the 4*G size.  Although I have to admit that 
HeapBaseMinAddress still mystifies me (for linux).

Thanks,
Coleen

On 1/23/15, 11:48 AM, Andrew Haley wrote:
> ... when it doesn't need to be.
>
> The reason for this is that we allocate the heap at the end of the
> lower 4*G region and we allocate the metaspace immediately after the
> heap, so we always need a nonzero narrow_klass_shift because
> narrow_klass_base is not less than 32 bits.
>
> If I set HeapBaseMinAddress=2g it's fine.
>
> The code which puts the heap right at the end of the lower 4*G region
> is quite deliberate:
>
>      // Return specified base for the first request.
>      if (!FLAG_IS_DEFAULT(HeapBaseMinAddress) && (mode == UnscaledNarrowOop)) {
>        base = heap_base_min_address_aligned;
>
>      // If the total size is small enough to allow UnscaledNarrowOop then
>      // just use UnscaledNarrowOop.
>      } else if ((total_size <= OopEncodingHeapMax) && (mode != HeapBasedNarrowOop)) {
>        if ((total_size <= UnscaledOopHeapMax) && (mode == UnscaledNarrowOop) &&
>            (Universe::narrow_oop_shift() == 0)) {
>          // Use 32-bits oops without encoding and
>          // place heap's top on the 4Gb boundary
>          base = (UnscaledOopHeapMax - heap_size);
>
> Why do we do this?  I carefully set HeapBaseMinAddress in the AArch64
> back end to a sensible value which would in many cases get me a zero
> narrow_klass_shift, but this code ignores the default.
>
> Thanks,
> Andrew.



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