RFR: 8185723: Zero: segfaults on Power PC 32-bit

coleen.phillimore at oracle.com coleen.phillimore at oracle.com
Thu Aug 3 12:03:03 UTC 2017


Hi,  Looks like a good find.  I think this should be on the list of 
things you can push directly from the open.
Otherwise, I'll sponsor it.  I didn't review it though.
Coleen

On 8/2/17 12:35 PM, Andrew Haley wrote:
> We've been seeing baffling segfaults in the C++ interpreter on Power
> PC 32-bit.
>
> Zero is so called because it uses zero assembly language, but this is
> not quite true: there is a tiny bit of assembly language, and it is
> wrong.  Here is the PPC32 definition of atomic_copy64.  It uses a
> floating-point register to copy a 64-bit doubleword atomically:
>
>    // Atomically copy 64 bits of data
>    static void atomic_copy64(volatile void *src, volatile void *dst) {
> #if defined(PPC32) && !defined(__NO_FPRS__)
>      double tmp;
>      asm volatile ("lfd  %0, 0(%1)\n"
>                    "stfd %0, 0(%2)\n"
>                    : "=f"(tmp)
>                    : "b"(src), "b"(dst));
>
> The eagle-eyed among you might have noticed the bug: this asm has no
> memory effect.  It has no memory inputs, no memory outputs, and no
> memory clobber.  So, as far as GCC is concerned atomic_copy64 does not
> touch memory at all, and there is no need to store the source operand
> into memory.  For all GCC knows, the asm might just be doing some
> arithmetic on the pointers.  We need a better definition of
> atomic_copy64, and this is mine:
>
>    // Atomically copy 64 bits of data
> static void atomic_copy64(volatile void *src, volatile void *dst) {
> #if defined(PPC32) && !defined(__NO_FPRS__)
>      double tmp;
>      asm volatile ("lfd  %0, %2\n"
>                    "stfd %0, %1\n"
>                    : "=&f"(tmp), "=Q"(*(volatile double*)dst)
>                    : "Q"(*(volatile double*)src));
>
> Note that we dereference src and dst and pass the actual memory
> operands to the asm, not just pointers to them.
>
> http://cr.openjdk.java.net/~aph/8185723/
>
> OK?
>



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