JDK 8 - Lambda - Reflection issues

Pavel Bucek pavel.bucek at oracle.com
Thu Mar 13 08:56:26 UTC 2014


Hi Remi,

thanks! I suspected that it would not be possible, but it is always 
better to have the confirmation.

My context is slightly different, but the consequences are similar like 
with the jackson library. Seems a little unfortunate to have the 
possibility to use lambdas even on places where it cannot work - my 
guess is that this will become one of most frequent question on some 
mailing lists..

(you don't really need to read further)

I'm working on JSR 356 - Java API for WebSocket implementation and there 
is an interface:

interface MessageHandler.Whole<T> extends MessageHandler {
     void onMessage(T message);
}

And then there is a Session object, which has method "void 
addMessageHandler(MessageHandler handler);". Obvious common use of this 
method is:

session.addMessageHandler(new MessageHandler.Whole<String>() {
     @Override
         public void onMessage(String message) {
             // ...
         }
});

I can see my IDE automatically offers me to transform this to lambda 
expression (this is actually what worries me a little, because all users 
will see that and do it - because why not - it seems to be equivalent 
with anonymous class). When this suggestion is accepted, previous 
statement is transformed into:

session.addMessageHandler((MessageHandler.Whole<String>) message -> {
     // ...
});

which looks prettier, but just does not work and cannot work :/ I guess 
we could provide wrapper class, something like:

     public static class WholeMessageHandler<T> implements 
MessageHandler.Whole<T> {

         private final Class<T> genericParam;
         private final MessageHandler.Whole<T> wholeMessageHandler;

         protected WholeMessageHandler(Class<T> genericParam, 
MessageHandler.Whole<T> wholeMessageHandler) {
             this.genericParam = genericParam;
             this.wholeMessageHandler = wholeMessageHandler;
         }

         public Class<T> getGenericParam() {
             return genericParam;
         }

         @Override
         public void onMessage(T message) {
             wholeMessageHandler.onMessage(message);
         }
     }

and then, when user would want to use lambdas, do it with help of that 
class:

session.addMessageHandler(new WholeMessageHandler<Main>(Main.class, 
param -> System.out.println("234")));

so I can do this like a workaround, but anyway, the initial 
recommendation of the IDE is bad enough to cause us lots of mailing list 
traffic and explanations why is not possible to use lambda in "native" 
fashion. Anyway - I'm not describing my pain just to share my pain - if 
anyone have any suggestions how this can be solved, I'm all ears; any 
reply would be greatly appreciated.

Thanks!
Pavel


On 12/03/14 19:42, Remi Forax wrote:
> On 03/12/2014 07:12 PM, Pavel Bucek wrote:
>> Hello all,
>>
>> I have an issue with getting generic parameter when using lambdas. I 
>> can get the type when using anonymous classes.
>>
>> code sample will be more descriptive than anything I would say, so.. :
>>
>> public class Main {
>>
>>     public static interface A<T> {
>>         public void method(T param);
>>     }
>>
>>     public static void main(String[] args) {
>>
>>         final A<Main> anonClass = new A<Main>() {
>>             @Override
>>             public void method(Main param) {
>>                 System.out.println("234");
>>             }
>>         };
>>
>>         final A<Main> lambda = param -> System.out.println("234");
>>
>>         //following does not help.
>>         // final A<Main> lambda = (A<Main>)param -> 
>> System.out.println("234");
>>
>>
>>         // output: Main.Main$A<Main>
>>         System.out.println("$ " + 
>> anonClass.getClass().getGenericInterfaces()[0]);
>>
>>         // output: interface Main$A          ### generic type info is 
>> already lost (no <Main>)
>>         System.out.println("# " + 
>> lambda.getClass().getGenericInterfaces()[0]);
>>
>>         // parameterized type from annon class
>>         final Type t = 
>> ((ParameterizedType)anonClass.getClass().getGenericInterfaces()[0]).getActualTypeArguments()[0];
>>         System.out.println("$ " + t);
>>
>>         // parameterized type from lambda
>>         System.out.println("# " + "???");
>>     }
>> }
>>
>> I was not able to find any useful documentation or article about 
>> this, so sorry if this is something common - feel free to RTM me 
>> (with relevant link please).
>>
>> Thanks and regards,
>> Pavel
>
> As you have seen a lambda is not an anonymous class :)
>
> A non-serializable lambda is more lightweight than an anonymous class 
> so the generic information that are transmitted from the bytecode to 
> the runtime (the lambda metafactory) are not kept inside the lambda 
> class (a lambda class may be shared by several different lambdas).
>
> A serializable lambda keep these information because you need them to 
> deserialize a lambda but they are not publicly available
> The current implementation encoded them in the bytecode and this 
> bytecode is not publicly available so unless you serialize the lambda 
> and serialize it by hand, you can not have access to these information.
>
> So you can not use a lambda with frameworks like Jackson that use the 
> TypeReference idiom,
> you can still use an anonymous class for that :)
>
> cheers,
> Rémi
>
>
>



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