Reflection: how does one access a protected member in a superclass reflectively?

[Alan Bateman]

On 17/01/2018 18:53, Rony G. Flatscher wrote:
>
> :
>
>
> Not with Java 9 javac, the following Java program:
>
>     public class TestUse
>     {
>         public static void main (String args[]) {
>             mtest3.Class03A o=new mtest3.Class03A();
>             System.out.println("o: "+o+", myClassName: "+o.myClassName);
>         }
>     }
>
> yields the error message:
>
>     F:\work\svn\bsf4oorexx\trunk\bsf4oorexx.dev\testUnits\bsf4rexx\java9modules>java
>     -cp ".;F:\work\svn\bsf4oorexx\trunk;.;C:\Program Files
>     (x86)\BSF4ooRexx\bsf4ooRexx-v600-20180101-bin.jar;C:\Program Files
>     (x86)\BSF4ooRexx\jni4net.j-0.8.8.0.jar;C:\Program Files
>     (x86)\BSF4ooRexx\oorexx.net.jar;." --module-path out --add-modules
>     mod_A,mod_B,mod_C TestUse
>     Exception in thread "main" java.lang.IllegalAccessError: tried to
>     access field mtest1.Class01A.myClassName from class TestUse
>             at TestUse.main(TestUse.java:5)
>
If it compiles then it should run so something isn't right here. I just 
tried this with JDK 9 and JDK 10 EA builds but couldn't duplicate it 
(the compilation fails as expected because myClassName has protected 
access in mod_A/mtest1.Class01A).

Would you mind zipping up the sources for mod_A, mod_B, and mod_C so we 
can duplicate this?

-Alan