Sample time with "inverted" histogram?
Chris Vest
mr.chrisvest at gmail.com
Fri Nov 27 16:08:11 UTC 2015
Hi,
I sometimes find myself wishing the sample time benchmark mode had an “inverse” histogram, because I find that this makes it easier to spot when response times are modal.
To demonstrate what I mean, the current histogram output looks like this: (numbers are fictive)
Samples, N = 3184
mean = 2.531 ±(99.9%) 0.014 us/op
min = 0.119 us/op
p( 0.0000) = 0.119 us/op
p(50.0000) = 2.420 us/op
p(90.0000) = 2.644 us/op
p(95.0000) = 2.816 us/op
p(99.0000) = 4.408 us/op
p(99.9000) = 13.152 us/op
p(99.9900) = 36.901 us/op
p(99.9990) = 254.240 us/op
p(99.9999) = 260.864 us/op
max = 260.864 us/op
And I would like a configuration option that would make it look more like this: (numbers even more fictive)
Samples, N = 3184
mean = 2.531 ±(99.9%) 0.014 us/op
min = 0.119 us/op
us/op = samples added in increment
1 = 1081
2 = 194
4 = 959
8 = 357
16 = 3
32 = 3
64 = 118
128 = 410
256 = 58
512 = 1
This way, I can more easily see that the numbers in my made-up example fall into 2 or 3 groups.
When I have needed something like this, I have thus far reached for HdrHistogram and its LogarithmicIterator, and the HistogramIterationValue.getCountAddedInThisIterationStep method.
Cheers,
Chris
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