Sample time with "inverted" histogram?

[Chris Vest]

Yes, that’s perfect.

Cheers,
Chris

> On 14 Jan 2016, at 15:07, Aleksey Shipilev <aleksey.shipilev at oracle.com> wrote:
> 
> On 01/11/2016 06:05 PM, Chris Vest wrote:
>>> On 11 Jan 2016, at 13:54, Aleksey Shipilev
>>> <aleksey.shipilev at oracle.com <mailto:aleksey.shipilev at oracle.com>> wrote:
>>> 
>>> It might be worthwhile to explore. JMH's SampleBuffer is recording the
>>> HDR data, so those histogram values are available. Therefore it is a
>>> question of presentation: maybe print the histogram alongside with
>>> quantiles?
>> 
>> You meaning putting both presentations side by side in the print out?
>> That would work for me.
> 
> So I have a patch that produces this. Is that what you are looking for?
> 
> -----------------------------------------------------------
> 
> Result "test":
>  N = 67526
>  mean =     16.117 ±(99.9%) 0.039 ns/op
> 
>  Percentiles:
>      p(0.0000) =     15.000 ns/op
>     p(50.0000) =     16.000 ns/op
>     p(90.0000) =     16.000 ns/op
>     p(95.0000) =     16.000 ns/op
>     p(99.0000) =     17.000 ns/op
>     p(99.9000) =     67.000 ns/op
>     p(99.9900) =     98.247 ns/op
>     p(99.9990) =    201.000 ns/op
>     p(99.9999) =    201.000 ns/op
>    p(100.0000) =    201.000 ns/op
> 
>  Histogram, ns/op:
>    [  0.000,  25.000) = 66908
>    [ 25.000,  50.000) = 462
>    [ 50.000,  75.000) = 140
>    [ 75.000, 100.000) = 11
>    [100.000, 125.000) = 3
>    [125.000, 150.000) = 1
>    [150.000, 175.000) = 0
>    [175.000, 200.000) = 0
>    [200.000, 225.000) = 1
>    [225.000, 250.000) = 0
>    [250.000, 275.000) = 0
> 
> -----------------------------------------------------------
> 
> Result "test":
>  N = 94842
>  mean =  52662.517 ±(99.9%) 19.244 ns/op
> 
>  Percentiles:
>      p(0.0000) =   2216.000 ns/op
>     p(50.0000) =  52608.000 ns/op
>     p(90.0000) =  52672.000 ns/op
>     p(95.0000) =  52672.000 ns/op
>     p(99.0000) =  53312.000 ns/op
>     p(99.9000) =  66304.000 ns/op
>     p(99.9900) = 174724.019 ns/op
>     p(99.9990) = 211456.000 ns/op
>     p(99.9999) = 211456.000 ns/op
>    p(100.0000) = 211456.000 ns/op
> 
>  Histogram, ns/op:
>    [     0.000,  25000.000) = 12
>    [ 25000.000,  50000.000) = 22
>    [ 50000.000,  75000.000) = 94774
>    [ 75000.000, 100000.000) = 13
>    [100000.000, 125000.000) = 7
>    [125000.000, 150000.000) = 2
>    [150000.000, 175000.000) = 4
>    [175000.000, 200000.000) = 7
>    [200000.000, 225000.000) = 1
>    [225000.000, 250000.000) = 0
>    [250000.000, 275000.000) = 0
> 
> -----------------------------------------------------------
> 
> Thanks,
> -Aleksey
>