New

[Peter Levart]

On 03/29/10, Howard Lovatt wrote:
> 2. It is compatible with the diamond operator from Coin (assuming <> are
> used), e.g.:
> 
>   List<Integer> list = new ArrayList<>();
>   #<int()> lambda = new #<>(42);
> 

How would diamond operator work for this example:

#int(int, int) add = #(int a, int b)(a+b);

Peter