Method reference conversion

[Brian Goetz]

Slight correction -- in this particular case (where the method reference is a bound instance reference), it seems quite unlikely that these references would be ==.  However, for static references and unbound instance references, it is quite likely that they will be ==.  In any case, it is unlikely the spec will make promises that are potentially expensive to keep.  

On Dec 15, 2011, at 4:10 PM, Brian Goetz wrote:

> Most likely outcome: no guarantees (such guarantees come with a cost) but it is "highly likely" that method1 == method2.  
> 
> When we finish the implementation of functional interface conversion we'll have a update.  
> 
> On Dec 15, 2011, at 3:35 PM, Uther wrote:
> 
>> Hello. I have been reading this mailing list from long time but didn't 
>> post anything right now since I'm not a Java expert, but I was 
>> wonderning about Method references.
>> 
>> Will every reference to a same method be converted to the same object? 
>> Will the language specification tell something about it?
>> 
>> For exemple:
>> Runnable method1 = this::myMethod;
>> Runnable method2 = this::myMethod;
>> System.out.println(method1 == method2); //returns true
>> 
>> I'm not sure it is technicaly possible, but it would be very nice that 
>> specification garantee that, it may allow to do interesting things like 
>> a removeListener(this::myListener) after a addListener(this::myListener);
>> 
> 
>