Optional brackets around lambda expression (was: Expected distribution of lambda sizes)

[Ali Ebrahimi]

Hi,
currently we don't have function types to support this use case, unless
change code as

Sam<Person,Integer> sam=#(Person x) {x.getAge()};

int ageOfJoe = sam.invoke(joe);


Ali Ebrahimi

On Thu, Jun 16, 2011 at 10:25 AM, Reinier Zwitserloot <
reinier at zwitserloot.com> wrote:

> My gut instinct was: That's a really bad idea. But I decided to play around
> with it anyway and it actually resulted in easier to scan code (to me,
> anyway). The use cases I've worked on before indeed usually boil down to
> passing the closure straight into a method as an argument, and in such
> cases
> it's better. As Pavel said, if you treat the closure preamble (the => or
> the
> #() or whatever the syntax calls for) as an operator with low precedence,
> it
> works out.
>
> This way the strawman syntax almost seems to have that best of both worlds
> scenario: It looks good both for long and one-liner closures. Passing
> closures inline as argument to a method, i.e. the map/filter usecase, looks
> a lot cleaner when you lose a closing brace/paren.
>
> Precedence-wise, if you want to exit the closure scope, you have to resort
> to this:
>
> int ageOfJoe = (#(Person x) x.getAge()).invoke(joe);
>
> which is different from what traditional strawman wanted you to do:
>
> int ageOfJoe = #(Person x) (x.getAge()).invoke(joe);
>
> Personally I found it easier to scan the new form vs. the old one (i.e. its
> easier to see in the top version that the toString applies just as much to
> the #(Person x) part as the x.getAge() part), so this is not necessarily a
> bad thing.
>
> I don't think its necessary but this proposal can be extended by allowing
> braces for single expressions, i.e:
>
> int ageOfJoe = #(Person x) {x.getAge()}.invoke(joe);
>
>  though I'm not sure how easy it is to implement this in an LL(k) parser
> (you'd have to conflate the first statement/expression as 'its one of those
> two', then scan for either a semicolon or the closing brace, at which point
> you have to go back and doublecheck that the statement or expression you
> parsed is actually an expression if there wasn't one, or actually a
> statement if there was. That's different than what javac currently does; it
> always knows if it wants a statement or an expression, it never needs to
> parse an 'it's one of those'. ecj will have any problem with this as it
> already junks statements and expressions into the same pile.
>
>
>  --Reinier Zwitserloot
>
>
>
> On Wed, Jun 15, 2011 at 10:42 PM, Pavel Minaev <int19h at gmail.com> wrote:
>
> > Note that this applies also to "Redmond syntax" in general; e.g.:
> >
> >   new User().use(x => x + "a string");
> >
> > However, I do not recall it ever being a problem in C# in practice, nor
> did
> > I ever hear of complaints about that in C#. In general, lambda syntax is
> > treated as a sort of "lambda operator" =>, with a certain "precedence",
> and
> > said "precedence" is lower than any other operator - in this case, lower
> > than "+". In that sense, it's not much different than correctly parsing
> > expressions such as a || b && c.
> >
> > On Wed, Jun 15, 2011 at 1:35 PM, Yuval Shavit <yshavit at akiban.com>
> wrote:
> >
> > > What would happen with something like:
> > >
> > >  public interface Sam {
> > >    String doSomething(String arg);
> > >  }
> > >  public class User {
> > >    public void use(Sam sam) { System.out.println("saw a sam"); }
> > >    public void use(String string) { System.out.println("saw a string");
> }
> > >  }
> > >
> > >  new User().use( #(x) x + "a string" );
> > >
> > > In that context, which are we passing?
> > >   - lambda that takes a String, concatenates "a string" to it and
> returns
> > > the result
> > >   - a string consisting of (lambda x -> x).toString() concatenated with
> > "a
> > > string"
> > >
> > > This is just one simple and somewhat contrived example, but the point
> is
> > > that without braces or something similar, it's not too hard to come up
> > with
> > > a situation where it's not clear where the lambda ends and the rest of
> > the
> > > expression begins.
> > >
> > > On Wed, Jun 15, 2011 at 4:18 PM, Steven Simpson <ss at comp.lancs.ac.uk>
> > > wrote:
> > >
> > > > On 13/06/11 21:10, Pavel Minaev wrote:
> > > > > Statement lambdas would typically be thus wrapped, yes
> > (coincidentally,
> > > > it's
> > > > > also why I'd prefer to have a separate form for expression lambdas
> > > which
> > > > > does not include the {} so as to be visually distinct from
> statement
> > > > > blocks).
> > > >
> > > > Yes, I think I'd appreciate that visual distinction too.  Is it
> > possible
> > > > to have an unambiguous expression syntax not requiring any form of
> > > > brackets around either the whole lambda or its body?:
> > > >
> > > >  #() 3
> > > >  #() 3 + 4
> > > >  #(x) x + 1
> > > >  #(x, y) x + y
> > > >
> > > > When used like this, they will likely be in argument lists, so they
> are
> > > > naturally delimited by commas and the list-terminating bracket, and
> > need
> > > > no brackets of their own.  IOW, #() would have quite a low
> precedence,
> > > > and any brackets put around it would be part of existing syntax (e.g.
> > > > for normal expressions and argument lists).
> > > >
> > > > If you had one lambda in the body of another, it will likely have to
> be
> > > > inside an enclosed call, whose brackets will naturally delimit it:
> > > >
> > > >  #(a) a + process(#(b) b * b) + 10
> > > >
> > > > If it wasn't so embedded, you could always put normal expression
> > > > brackets around it:
> > > >
> > > >  #(a) a + (#(b) b * b).invoke(a)
> > > >
> > > > (And that's a little contrived.  And possibly quite difficult to
> > > > type-infer…?)
> > > >
> > > > I don't think you could drop the parameter-list brackets too, as that
> > > > would make parsing much more complex (e.g. #a + a).  Looking at that
> > > > more positively, it would keep lambda syntax and appearance obviously
> > > > distinct from method literals.  ("#(" => Bam!  I'm a lambda!)  The
> > > > presence of braces would then further distinguish lambda expressions
> > > > from lambda statements.
> > > >
> > > > In summary, we require brackets around neither the lambda expression
> > nor
> > > > its body.  We are then forced to used some around the parameter list,
> > > > but take advantage of this as the constant discriminant of lambda vs
> > > > method literal.
> > > >
> > > > Applied to some other expressions seen on the list lately:
> > > >
> > > >   list.filter( #(t) t.length() > 3 )
> > > >       .map( #(t) t.barCount )
> > > >       .max();
> > > >
> > > >   students.filter(#(s) s!=null && "Smith".equals(s.getName()))
> > > >
> > > >   List men = personList.filter(#(p) p.isMale());
> > > >
> > > >   List<Double> adjustedPrices =
> > > >      prices.map(#(price) price + getShipping());
> > > >
> > > > Cheers,
> > > >
> > > > Steven
> > > >
> > > >
> > > >
> > >
> > >
> >
> >
>
>