Syntax for calling super

[David Holmes]

On 23/08/2012 11:09 AM, Brenden Towey wrote:
> On 8/22/2012 3:32 PM, Yuval Shavit wrote:
>> To my mind, the syntax "should" be K.m() (without the super). That makes
>
>
> I'd tend to agree, except for the problems you mention.  What about
> "J.super.m()"?  "Don't call me call my parent class?"
>
> interface J extends K {
>      int m() default { return J.super.m(); }  // calls J's parent's m()
> }

The problem with that is that you need to be able to select from 
multiple parents, so the parent's type has to be in there somewhere.

David