lambda expression parameters

[Brian Goetz]

Agreed that this is something that has the right "nudge" to it.

One downside is that there is no keyword for "not final."  Which means 
this is not a question about "final by default", but "final by decree", 
unless we're willing to introduce new syntax for mutable (which we're 
not.)  That's not terrible -- most people would probably never even 
notice.  So, reasonable suggestion.



On 12/18/2012 4:40 PM, Venkat Subramaniam wrote:
> Hi
>
> Is there plans to make the inferred parameter of a lambda expression final by default.
> Right now, we can't specify the parameter is final unless we provide it with the type.
>
> In the spirit of leaning towards immutability, which is a better practice, would it be possible to
>
> (a) make all inferred parameters of lambda expressions final, and
> (b) to make it non-final, force the developers to explicitly request (like the mutable in F#).
>
> It's more of a wish-list, if that's something that can be considered.
>
> Thanks,
>
> Venkat
>