Code refuses to compile when using comparator with lambda

[Maurizio Cimadamore]

On 20/03/13 11:17, Remi Forax wrote:
> bitten by the wildcard capture, again
It's not that this time.

Juts the fact that the two methods are like:

<A> m(Function<? super A, ...>)

and

<B> m(Function<? super B, ...>)

Which means the two descriptors are:

A->...
B->...

So, does the first descriptor accept the same argument type as the 
second? No. (Or yes, but after alpha-renaming).

Maurizio