Lambda behaving differently than anonymous inner class

Vicente-Arturo Romero-Zaldivar vicente.romero at oracle.com
Wed May 7 14:19:57 UTC 2014


Hi Victor,

The bug you reported [1] has already been fixed,

Thanks,
Vicente

[1] https://bugs.openjdk.java.net/browse/JDK-8038420

On 26/03/14 19:32, Zhong Yu wrote:
> Another example:
>
>          Consumer<Integer> c = t -> System.out.println(t++);
>          c.accept(2);
>
> no no no no...
>
> Zhong Yu
>
>
> On Wed, Mar 26, 2014 at 10:03 AM, Victor Antunes
> <victor.antunes.ignacio at gmail.com> wrote:
>> Hello all,
>>
>> This e-mail is a follow-up to a question I've posted on StackOverflow:
>> http://stackoverflow.com/questions/22648079/lambda-behaving-differently-than-anonymous-inner-class
>>
>>
>> I'm relatively new to Java, and decided to pick up on lambda since the past
>> few days. So I wrote a very simple anonymous inner class and wrote an
>> equivalent lambda.
>>
>> However, the lambda output was different, and it very strongly appears to
>> be a bug.
>>
>> Given:
>>
>> interface Supplier<T> {
>>
>>      T get(T t);}
>>
>> Supplier<Integer> s1 = new Supplier<Integer>() {
>>      @Override
>>      public Integer get(Integer t) {
>>          return t++;
>>      }};Supplier<Integer> s2 = t ->
>> t++;System.out.println(s1.get(2));System.out.println(s2.get(2));
>>
>> The output is 2 and 3, NOT 2 and 2, as one would expect.
>>
>> More info, including discussion about bytecode is available at the SO link
>> above.
>>
>> I'm also new to this list, so apologies if I've broken any mailing list
>> etiquette.
>>
>> --
>> Kind regards,
>>
>> Victor Antunes
>>



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