Map.asFunction

[Remi Forax]

On 01/04/2013 04:29 PM, Brian Goetz wrote:
> We didn't decide not to.  (Similarly Set.asPredicate())  No objection 
> (the body can be this::get).  No objection.
>
> On 1/4/2013 10:17 AM, Doug Lea wrote:
>>
>> There is no Map interface method:
>>
>>    default Function<K,V> asFunction() { return { k -> get(k) }; }
>>
>> Did we decide not to do this or just forget to do it?
>>
>> -Doug

Not sure it worth a method as it can be written map::get or set::contains.

Rémi