Loose end: concat

[Joe Bowbeer]

Why was an instance method rejected?  I can't recall.

s = s1.concat(s2).concat(s3);




On Thu, May 23, 2013 at 11:23 AM, Sam Pullara <spullara at gmail.com> wrote:

> *Stream seems like the right place for them to me. It is certainly the
> second place I would look — first place would be as an instance method, but
> we've discussed that before.
>
> Sam
>
> On May 23, 2013, at 11:06 AM, Brian Goetz <brian.goetz at oracle.com> wrote:
>
> > I cleaned up concat() and wrote Int/Long/Double versions.  (Fortunately,
> with the recent addition of Spliterator.OfPrimitive, the duplication
> quotient was much lower.)
> >
> > Currently these still live in Streams.  Is that still the right place?
> The stream classes (Stream, IntStream, etc) seem a little wrong for them,
> but I can't quite put my finger on why.
> >
> > Specs:
> >
> >    /**
> >     * Creates a lazy concatenated {@code Stream} whose elements are all
> the
> >     * elements of a first {@code Stream} succeeded by all the elements
> of the
> >     * second {@code Stream}. The resulting stream is ordered if both
> >     * of the input streams are ordered, and parallel if either of the
> input
> >     * streams is parallel.
> >     *
> >     * @param <T> The type of stream elements
> >     * @param a the first stream
> >     * @param b the second stream to concatenate on to end of the first
> >     *        stream
> >     * @return the concatenation of the two input streams
> >     */
> >    public static <T> Stream<T> concat(Stream<? extends T> a, Stream<?
> extends T> b) {
> >
> >
> >    /**
> >     * Creates a lazy concatenated {@code IntStream} whose elements are
> all the
> >     * elements of a first {@code IntStream} succeeded by all the
> elements of the
> >     * second {@code IntStream}. The resulting stream is ordered if both
> >     * of the input streams are ordered, and parallel if either of the
> input
> >     * streams is parallel.
> >     *
> >     * @param a the first stream
> >     * @param b the second stream to concatenate on to end of the first
> stream
> >     * @return the concatenation of the two streams
> >     */
> >    public static IntStream concat(IntStream a, IntStream b) {
> >
> >
> > (and similar for Long and Double).
> >
>
>
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