Stream + BaseStream

[Paul Sandoz]

On Dec 16, 2013, at 11:23 PM, Kasper Nielsen <kasperni at gmail.com> wrote:

> Hi,
> 
> IntStream/LongStream/DoubleStream all override
> 
> sequential(), parallel(), unordered(), ... from BaseStream.
> 
> However Stream does not override this methods

It does:

  public interface Stream<T> extends BaseStream<T, Stream<T>>


> so you have to cast the
> stream if you are you a using a non-parameterized stream, as in:
> Stream s = *null*;
> s = (Stream) s.unordered();
> 

Because a raw-typed Stream is used, and therefore a raw type for BaseStream, the compiler cannot infer S and has to resort to using the upper bound, BaseStream:

  public interface BaseStream<T, S extends BaseStream<T, S>>

Using a raw type for Stream will also have other consequences for type inference when chaining operations. I have seen a number of examples highlighting issues (posted to various lists) that were in part broken because a raw type for Stream was used. I would recommend avoiding such use if at all possible.

Paul.