MethodHandleInfo.getDeclaringClass()

[Peter Levart]

Hi,

The following code:

public class Test {

     static class X {
         public void x() { }
     }

     static class Y extends X {
     }

     public static void main(String[] args) throws Exception {
         MethodHandles.Lookup lookup = MethodHandles.lookup();
         MethodHandle mh = lookup.findVirtual(Y.class, "x", 
MethodType.methodType(void.class, new Class[0]));
         MethodHandleInfo mhi = lookup.revealDirect(mh);
         System.out.println(mhi.getDeclaringClass().getSimpleName());
     }
}


...prints "Y". Is this correct? The javadoc for the method says:


/Returns the class in which the cracked method handle's underlying 
member was defined.//
//
//Returns://
//        the declaring class of the underlying member/


The "declaring" class of the underlying member (the method x()) is 
clearly not class Y,  but class X, isn't it?

Regards, Peter

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