How to set correct fileName for exceptions thrown from a function in a Function object

[A. Sundararajan]

you can use

1) "load" from object - object with name and script properties.

2) or use 'eval' naming // #sourceURL comment

as mentioned here:

http://mail.openjdk.java.net/pipermail/nashorn-dev/2014-July/003174.html

Can code for body of module function be something like 
"eval(readScriptAsText() + "\n// #sourceURL=" + name)" ?

Hope this helps,
-Sundar

On Wednesday 18 February 2015 03:30 PM, Tim Fox wrote:
> I've added a simple reproducer that you can run in the repl:
>
> https://gist.github.com/purplefox/b03a2a6263c26e3206da
>
> Another observation is that line number is reported as 6, when it 
> should be 5 (assuming the first line is line 1 which is normal 
> convention afaik)
>
> On 18/02/15 09:40, Tim Fox wrote:
>> Hi all,
>>
>> I'm currently using a CommonJS/npm modules require implementation 
>> (npm-jvm) with Nashorn.
>>
>> Roughly, the way it works (and I'm sure you're already familiar with 
>> this technique) is it takes the JavaScript module and wraps it in a 
>> Function object:
>>
>> var body = readScriptAsText();
>> var args   = ['exports', 'module', 'require', '__filename', 
>> '__dirname'];
>> var func = new Function(args, body);
>> func.apply(module, [module.exports, module, module.require, 
>> module.filename, dir]); // Execute it - this works fine
>>
>> Now let's say the actual module (foomodule.js) we are loading 
>> contains this:
>>
>> module.exports = function() {
>>     var num = 234;
>>     num.substr(1, 1); // Will throw TypeError here
>> }
>>
>> I.e. it simply exports a function, which will throw a TypeError when 
>> it's executed.
>>
>> When the exported function is executed it does indeed throw a TypeError:
>>
>> var f = require("foomodule");
>>
>> f(); // Throws TypeError
>>
>> Unfortunately the fileName field of the TypeError is set to 
>> "<function>" not to "foomodule.js", which is unfriendly for the user.
>>
>> This is understandable as the Function object which wraps the module 
>> doesn't know about "foomodule.js".
>>
>> So.. my question is.. how do I tell the Function object that the 
>> "filename" it should use when exceptions are thrown from it is 
>> "foomodule.js"?
>>
>> I have tried the following and none work:
>>
>> var func = new Function(args, body);
>> func.name = "foomodule.js";
>> func.fileName = "foomodule.js";
>> func.displayName = "foomodule.js";
>>
>> Any insights would be greatly appreciated.
>>
>>
>>
>>
>