does the underlying implementation (not public) of DatagramSocketImp's send receive method busy wait

[Alan Bateman]

On 18/12/2017 21:24, Paul Marks wrote:
>
>
> So if the kernel decides to block, the thread will be suspended 
> (consuming no CPU) until it's done.
>
> However, the UDP protocol has no concept of flow control, so blasting 
> out packets without any rate limit or acknowledgement mechanism is not 
> a good idea.  If you saturate a link in the network, sendto() is not 
> obligated to block, or provide any feedback whatsoever.
That's right and you'll find that most kernels will just discard the 
packet so the send never blocks.

-Alan
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