Doubts on LinearGradient#proportional=true

[Tom Schindl]

well then would be a negative value not?

Tom

Am 08.06.12 16:55, schrieb Gerrit Grunwald:
> Ok got it, but it seems the gradient coordinates are related to the
> complete drawing area instead of the node which makes sense to me.
> Otherwise you won't be able to create gradients outside of the bounds of
> a node right ?
> 
> Am 08.06.2012 um 16:50 schrieb Tom Schindl:
> 
>>>>> Group g = new Group();
>>>>> Rectangle r = new Rectangle(40,0,90,75);
>>>>> List<Stop> stops = new ArrayList<Stop>();
>>>>> stops.add(new Stop(0, Color.RED));
>>>>> stops.add(new Stop(1, Color.BLUE));
>>>>> LinearGradient lg = new LinearGradient(0, 0, 90, 0, false,
>>>>> CycleMethod.NO_CYCLE, stops);
>>>>> r.setFill(lg);
>>>>> g.getChildren().add(r);
> 


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