Implement no copy memory
Ardika Rommy Sanjaya
ardikars at gmail.com
Mon May 20 01:44:46 UTC 2019
Hi,
> It looks like pamana copy value from 'u_char *' into 'Pointer<Byte> buf', correct or not? Because when I call buf.addr() it returns 0, what zero mean?
> How I can do with no copy? Just returns the address of 'u_char *' like below in callback method?
Returns 0 when call buf.addr() is fixed, but I got another issue. buf.addr() always returns same address.
Regards,
Ardika Rommy Sanjaya
---
> On 20 May 2019, at 06.33, Ardika Rommy Sanjaya <ardikars at gmail.com> wrote:
>
> Hi,
>
> There is native function in libpcap library: typedef void (*pcap_handler)(u_char *, const struct pcap_pkthdr *, const u_char *);
> When I use jextract it generate code like below:
>
> @NativeHeader(...)
> public interface pcap_h {
>
> ...
>
> @NativeLocation(...)
> @NativeFunction("(u64:${pcap}i32u64:(u64:u8u64:${pcap_pkthdr}u64:u8)vu64:u8)i32")
> int pcap_loop(Pointer<pcap> p, int cnt, Callback<pcap_handler> callback, Pointer<Byte> usr);
>
> @FunctionalInterface
> @NativeCallback("(u64:u8u64:${pcap_pkthdr}u64:u8)v")
> interface pcap_handler {
>
> void fn(Pointer<Byte> buf, Pointer<pcap_pkthdr> pkthdr, Pointer<Byte> usr) throws IllegalAccessException;
>
> }
>
> ...
>
> }
>
> It looks like pamana copy value from 'u_char *' into 'Pointer<Byte> buf', correct or not? Because when I call buf.addr() it returns 0, what zero mean?
> How I can do with no copy? Just returns the address of 'u_char *' like below in callback method?
>
> void fn(long memoryAddressOf_u_char_ptr, Pointer<pcap_pkthdr> pkthdr, Pointer<Byte> usr) throws IllegalAccessException;
>
> Thanks and Regards,
> Ardika Rommy Sanjaya
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