Byte.parseByte throws NumberFormatException for value "95", radix: 16
Janda Martin
jandam at crcdata.cz
Tue Jul 12 11:32:31 UTC 2011
I have question about parsing hex string. Java 6u25
When I call Byte.parseByte("95", 16) I get.
java.lang.NumberFormatException: Value out of range. Value:"95" Radix:16
at java.lang.Byte.parseByte(Byte.java:153)
95 hex is 149 dec, Integer value '149' can be cast to valid byte value -107
Is the exception correct?
Thank you very much for answer
Martin JANDA
jandam at crcdata.cz
Code from Byte.java
public static byte parseByte(String s, int radix)
throws NumberFormatException {
int i = Integer.parseInt(s, radix);
if (i < MIN_VALUE || i > MAX_VALUE)
throw new NumberFormatException(
"Value out of range. Value:\"" + s + "\" Radix:" + radix);
return (byte)i;
}
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