JDK 9 RFR(s): 8150488: add note toScanner.findAll()regardingpossible infinite streams

Timo Kinnunen timo.kinnunen at gmail.com
Wed Apr 5 06:31:06 UTC 2017


Then Scanner.findAll() should be specified not in terms of findWithinHorizon() but something else, maybe Matcher.find(). If it’s specified using findWithinHorizon() this would require implementations of its backing regex engine to be inferior or even broken in this respect when compared to other regex engines. If a regex engine chosen for an implementation didn’t have infinite looping then that would have to be emulated!






Sent from Mail for Windows 10

From: Stuart Marks
Sent: Wednesday, April 5, 2017 07:50
To: Timo Kinnunen
Cc: Xueming Shen; core-libs-dev at openjdk.java.net
Subject: Re: JDK 9 RFR(s): 8150488: add note toScanner.findAll()regardingpossible infinite streams



On 4/4/17 5:33 PM, Timo Kinnunen wrote:
Hi, 
 
I agree, the behavior should change to work like Matcher.find() which is probably the better known API. E.g. http://www.regular-expressions.info/continue.html describes Java’s Matcher’s behavior on empty matches but doesn’t mention any other APIs beside that.
I don't think Sherman was suggesting that.

In any case this would be a change to findWithinHorizon(), which isn't in scope.

s'marks

 
If we say a regex engine’s task is to find non-overlapping matches in a given input then it repeatedly returning the same empty match at the same location could even be considered a bug.
 
 
 
Sent from Mail for Windows 10
 
From: Xueming Shen
Sent: Wednesday, April 5, 2017 01:11
To: Stuart Marks
Cc: Timo Kinnunen; core-libs-dev at openjdk.java.net
Subject: Re: JDK 9 RFR(s): 8150488: add note to Scanner.findAll()regardingpossible infinite streams
 
On 4/4/17, 12:52 PM, Stuart Marks wrote:
> Anything further on this?
> 
> I'd at least like to add the API note I proposed in order to document 
> this issue. I'm reluctant to start tinkering with the behavior of this 
> method at this late stage in the release.
> 
> BTW I used Scanner.findAll() in a little programming exercise I worked 
> on the other day. It worked perfectly. :-)
 
H Stuart,
 
The word "useless" was definitely exaggerate :-) Really meant to say the 
note might make the api less
useful/popular.
 
Personally I think the use scenario and the expected resulting behavior 
of Stream<MR>finaAll(ptn)
should be more equivalent/similar to the use case  of while 
(s.hasNext(p)) {   s.next(p); }, or while
(m.find()) { }, therefor it is probably desired it can be used without 
worrying the possibility of getting
into an infinite loop. That said, I agree it might be hard to argue to 
fix it in jdk9. The question is if
we are going to fix it in 9u sometime in the further, is it still worth 
putting down the note in the
API now. I'm fine if you believe a note will help at least make the 
issue a known/documented usage
limitation, for JDK9.
 
Yes, I think we did chat about this one at the hallway some time when 
either you or something
ran into the loop by using the method ...
 
Thanks,
Sherman
 
 
> 
> s'marks
> 
> On 3/30/17 2:19 PM, Stuart Marks wrote:
>> Hi Timo, Sherman,
>> 
>> Thanks for looking at this.
>> 
>> Sherman wrote:
>> 
>>> This might practically put the api itself almost useless? it might 
>>> be an easy
>>> task to spot
>>> whether or not it's a 0-width-match-possible regex when the regex is 
>>> simple,
>>> but it gets
>>> harder and harder, if not impossible when the regex gets complicated,
>>> especially consider
>>> the possible use scenario that the use site is embedded deeply inside a
>>> library implementation.
>> 
>> Well, not "useless", but perhaps less useful than one might like. :-)
>> 
>> I think this is potentially surprising behavior, which is why I at 
>> least wanted
>> to add the note. It's not clear to me whether we should try to fix 
>> this by
>> changing Scanner though.
>> 
>> Essentially, findAll() is defined in terms of 
>> findWithinHorizon(pattern, 0). So
>> if one were to write a loop like so:
>> 
>>     String str;
>>     while ((str = scanner.findWithinHorizon(pattern, 0)) != null) {
>>         System.out.println(str);
>>     }
>> 
>> then this loop would have the same problem if pattern were to match zero
>> characters.
>> 
>>> The alternative is to "fix" it, maybe as what Matcher.find() does, 
>>> if the
>>> previous match is
>>> zero-width-match (the fist==last), we step one to the next cursor 
>>> before next
>>> try. I know
>> 
>> Interesting, I didn't know Matcher.find() advances the cursor like 
>> this. But
>> Scanner.findWithinHorizon() apparently doesn't, so that's why an 
>> infinite loop
>> can occur.
>> 
>>> Scanner.findPatternInBuffer() is setting new region set every time 
>>> it is
>>> invoked which makes
>>> it complicated, but I would assume it might be still worth a trying? 
>>> for
>>> example, utilize the
>>> "hasNextResult"/matcher.end(). I'm not sure without looking into the 
>>> code, does
>>> 
>>> while (hasNext(pattern)) {
>>>     next(pattern);
>>> }
>>> 
>>> have the same issue, when pattern matches 0-width?
>> 
>> No, this doesn't have the problem, because hasNext(pat) and next(pat) 
>> match
>> delimited tokens. Each call to next() implicitly advances past the next
>> delimiter to reach the subsequent token, if any.
>> 
>> 
>> On 3/30/17 8:56 AM, Timo Kinnunen wrote:
>>> I guess this somewhat contrived example also wouldn’t work?
>>> 
>>>         String s = "\\b\\w+|\\G|\\B";
>>>         String t = "Matcher m = Pattern.compile(s).matcher(t);\n";
>>>         Matcher m = Pattern.compile(s).matcher(t);
>>>         while(m.find()) {
>>>             System.out.println("'" + m.group() + "'");
>>>         }
>> 
>> Right, so if you rewrote this loop to use Scanner.findWithinHorizon() 
>> instead of
>> Matcher,
>> 
>>     Scanner sc = new Scanner(t);
>>     String str;
>>     while ((str = sc.findWithinHorizon(s, 0)) != null) {
>>         System.out.println("'" + str + "'");
>>     }
>> 
>> you'd get an infinite loop with str being continually assigned the 
>> empty string.
>> As Sherman mentioned, the Matcher.find() will advance the cursor if 
>> it gets a
>> zero-width match, avoiding this problem.
>> 
>> * * *
>> 
>> This didn't come up in the code review thread, which was mostly about 
>> concurrent
>> modification and late-binding of the spliterator:
>> 
>>   
>> http://mail.openjdk.java.net/pipermail/core-libs-dev/2015-September/035034.html
>> 
>> I remember noting this phenomenon a while back, which is why I had 
>> filed the bug
>> to add a note. I seem to remember discussing it, though, but it might 
>> have been
>> in a meeting or in a hallway conversation.
>> 
>> This bug (JDK-8150488) does note that an infinite stream might be 
>> unexpected or
>> surprising, but it's not a fatal problem. It can be terminated with 
>> limit(). It
>> can also be terminated with takeWhile(), also added in JDK 9. Maybe I 
>> could
>> mention these in the API note.
>> 
>> I guess we could also consider changing the implicit 
>> findWithinHorizon() loop
>> that findAll() does, perhaps by having it terminate on a zero-width 
>> match. Or we
>> could even change findWithinHorizon's behavior if it gets a 
>> zero-width match,
>> siilar to what Matcher.find() does. But I'm quite reluctant to start 
>> making such
>> changes at this point.
>> 
>> s'marks
>> 
>> 
>> 
>>>         // Outputs:
>>>         // 'Matcher'
>>>         // ''
>>>         // 'm'
>>>         // ''
>>>         // ''
>>>         // ''
>>>         // 'Pattern'
>>>         // ''
>>>         // 'compile'
>>>         // ''
>>>         // 's'
>>>         // ''
>>>         // ''
>>>         // 'matcher'
>>>         // ''
>>>         // 't'
>>>         // ''
>>>         // ''
>>>         // ''
>>>         // ''
>>> 
>>> 
>>> 
>>> Sent from Mail for Windows 10
>>> 
>>> From: Xueming Shen
>>> Sent: Thursday, March 30, 2017 05:41
>>> To: core-libs-dev at openjdk.java.net
>>> Subject: Re: JDK 9 RFR(s): 8150488: add note to Scanner.findAll()
>>> regardingpossible infinite streams
>>> 
>>> On 3/29/17, 5:56 PM, Stuart Marks wrote:
>>>> Hi all,
>>>> 
>>>> Please review these non-normative textual additions to the
>>>> Scanner.findAll() method docs. These methods were added earlier in JDK
>>>> 9; there's a small pitfall if the regex can match zero characters.
>>>> 
>>> Stuart,
>>> 
>>> This might practically put the api itself almost useless? it might 
>>> be an
>>> easy task to spot
>>> whether or not it's a 0-width-match-possible regex when the regex is
>>> simple, but it gets
>>> harder and harder, if not impossible when the regex gets complicated,
>>> especially consider
>>> the possible use scenario that the use site is embedded deeply inside a
>>> library implementation.
>>> 
>>> The alternative is to "fix" it, maybe as what Matcher.find() does, if
>>> the previous match is
>>> zero-width-match (the fist==last), we step one to the next cursor 
>>> before
>>> next try. I know
>>> Scanner.findPatternInBuffer() is setting new region set every time 
>>> it is
>>> invoked which makes
>>> it complicated, but I would assume it might be still worth a trying? 
>>> for
>>> example, utilize the
>>> "hasNextResult"/matcher.end(). I'm not sure without looking into the
>>> code, does
>>> 
>>> while (hasNext(pattern)) {
>>>      next(pattern);
>>> }
>>> 
>>> have the same issue, when pattern matches 0-width?
>>> 
>>> Thanks!
>>> -Sherman
>>> 
>>> 
>>> 
>>> 
>>>> Thanks,
>>>> 
>>>> s'marks
>>>> 
>>>> 
>>>> # HG changeset patch
>>>> # User smarks
>>>> # Date 1490749958 25200
>>>> #      Tue Mar 28 18:12:38 2017 -0700
>>>> # Node ID 6b43c4698752779793d58813f46d3687c17dde75
>>>> # Parent  fb54b256d751ae3191e9cef42ff9f5630931f047
>>>> 8150488: add note to Scanner.findAll() regarding possible infinite
>>>> streams
>>>> Reviewed-by: XXX
>>>> 
>>>> diff -r fb54b256d751 -r 6b43c4698752
>>>> src/java.base/share/classes/java/util/Scanner.java
>>>> --- a/src/java.base/share/classes/java/util/Scanner.java    Mon Mar 27
>>>> 15:12:01 2017 -0700
>>>> +++ b/src/java.base/share/classes/java/util/Scanner.java    Tue Mar 28
>>>> 18:12:38 2017 -0700
>>>> @@ -2808,6 +2808,10 @@
>>>>       * }
>>>>       * }</pre>
>>>>       *
>>>> +     * <p>The pattern must always match at least one character. If
>>>> the pattern
>>>> +     * can match zero characters, the result will be an infinite 
>>>> stream
>>>> +     * of empty matches.
>>>> +     *
>>>>       * @param pattern the pattern to be matched
>>>>       * @return a sequential stream of match results
>>>>       * @throws NullPointerException if pattern is null
>>>> @@ -2829,6 +2833,11 @@
>>>>       *     scanner.findAll(Pattern.compile(patString))
>>>>       * }</pre>
>>>>       *
>>>> +     * @apiNote
>>>> +     * The pattern must always match at least one character. If the
>>>> pattern
>>>> +     * can match zero characters, the result will be an infinite 
>>>> stream
>>>> +     * of empty matches.
>>>> +     *
>>>>       * @param patString the pattern string
>>>>       * @return a sequential stream of match results
>>>>       * @throws NullPointerException if patString is null
>>> 
>>> 
 
 




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