Syntax for calling super

[Yuval Shavit]

What about borrowing syntax from generic methods? super<K>.m()  (This is
different, albeit potentially confusingly, from super.<K>m()).

On Wed, Aug 22, 2012 at 9:09 PM, Brenden Towey <brendentowey at gmail.com>wrote:

> On 8/22/2012 3:32 PM, Yuval Shavit wrote:
> > To my mind, the syntax "should" be K.m() (without the super). That makes
>
>
> I'd tend to agree, except for the problems you mention.  What about
> "J.super.m()"?  "Don't call me call my parent class?"
>
> interface J extends K {
>     int m() default { return J.super.m(); }  // calls J's parent's m()
> }
>
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>