A syntax option (function types versus arrays)

[Peter Levart]

On Tuesday 02 March 2010 08:49:54 Peter Levart wrote:
> for void lambdas "void" keyword could be defined as expression of type void:
> 
> (->void) lambda = (-> System.out.println("Hello!"); void);
> 

Oops, this would make an ambiguous syntax:

	(->void) lambda = (->void);

Or is this still unambiguous since type and expression appear in different contexts?

Peter