RFR: 8356557: Update CodeSource::implies API documentation and deprecate java.net.SocketPermission class for removal [v2]
Sean Mullan
mullan at openjdk.org
Thu Jul 17 16:58:47 UTC 2025
On Thu, 17 Jul 2025 16:11:00 GMT, Jaikiran Pai <jpai at openjdk.org> wrote:
>>> Hello Sean, the original text in `SocketPermission.implies()` lists these 2 rules separately, as follows:
>>>
>>> > <li>If this object was not initialized with a single IP address, and one of this object's IP addresses equals one of p's IP addresses.
>>> > <li>If this canonical name equals p's canonical name.
>>>
>>> Given that we state at the beginning of this text that `the following checks are made in order:`, do you think we should continue to list these 2 rules separately, in that order, instead of combining them into one, like what's being proposed here?
>>
>> This one was a little tricky. `CodeSource.implies` states the following at the beginning:
>>
>> "More specifically, this method makes the following checks. If any fail, it returns false. If they all succeed, it returns true."
>>
>> That logic made sense prior to this fix because the rule said:
>>
>> "If this object's host (getLocation().getHost()) is not null, then the SocketPermission constructed with this object's host must imply the SocketPermission constructed with codesource's host."
>>
>> But if I just copy over the relevant conditions as-is from `SocketPermission.implies`, the last two conditions are not logically the same:
>>
>> - If this object was not initialized with a single IP address, and one of this object's IP addresses equals one of p's IP addresses.
>> - If this canonical name equals p's canonical name.
>>
>> If the first condition fails above, it doesn't bail out and return false, instead it checks the last condition. So this is why I combined those two conditions and added an "or".
>>
>> Let me know if this makes sense or if you think there is a better way to word this.
>
> After you mentioned this detail, I read this doc in its entirety. Would something like the following be a bit more clear:
>
>
>
> * <li> If this object's host (getLocation().getHost()) is not null,
> * then the following checks are made in that order and if any
> * of these checks are satisfied, then return true:
> * <ol>
> * <li> If this object's host was initialized with a single IP
> * address then one of <i>codesource</i>'s IP addresses must be
> * equal to this object's IP address.
> * <li> If this object's host is a wildcard domain (such as
> * *.example.com), then <i>codesource</i>'s canonical host name
> * (the name without any preceding *) must end with this object's
> * canonical host name. For example, *.example.com implies
> * *.foo.example.com.
> * <li> If this object's host was not initialized with a single
> * IP address, then one of this object's IP addresses must equal
> * one of <i>codesource</i>'s IP addresses.
> * <li> This object's canonical host name must equal <i>codesource</i>'s
> * canonical host name.
>
>
>
>
> Also note that, in the above text I used `<ol>` instead of `<ul>` to show the ordering intent. However, if the use of `<ul>` was intentional for better rendering, then that's fine too.
It's not the same logic. Even if the checks above pass, `implies()` does not return true yet, it still has to process the rules after that. I think you could say "... and if any of these checks are not satisfied, then return false" but that is somewhat redundant with the first sentence of `implies()`: "More specifically, this method makes the following checks. If any fail, it returns false. If they all succeed, it returns true."
-------------
PR Review Comment: https://git.openjdk.org/jdk/pull/26300#discussion_r2213851416
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